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At 25 degrees celsius only .0640 mol of the generic salt AB2 is soluble in 1.00...

At 25 degrees celsius only .0640 mol of the generic salt AB2 is soluble in 1.00 L of water. What is the Ksp of the salt at 25 degrees celsius. I got 1.0 X 10^-3 but the computer says its wrong. Plse help

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Expert Solution

Solubility of AB2 salt is S = number of moles / Volume in L

                                      = 0.0640 mol / 1.00L

                                      = 0.0640 M

   AB2A2+ + 2B-

So [A2+ ] = S

     [ B-] = 2S

Solubility product, Ksp = [A2+][B-] 2

                                 = S x (2S)2

                                 = 4S3

                                 = 4(0.0640)3

                                = 1.048x10-3

Therefore the solubility product of the salt is 1.048x10-3

queen_honey_blossom answered 1 hour ago
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