At 25 °C only 0.0500 mol of the generic salt AB is soluble in 1.00 L...

At 25 °C only 0.0500 mol of the generic salt AB is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C?

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Expert Solution

no of moles of AB salt = 0.05 moles

volume of solution = 1L

molarity of AB salt = no of moles/volume in L

= 0.05/1 = 0.05 M

AB(s) --------------------> A^+ (aq) + B^- (aq)

s s

Ksp = [A^+][B^-]

= s^s

Ksp = S^2

= (0.05)^2 = 0.0025 >>>>>answer

queen_honey_blossom answered 1 year ago

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