Question

At 25 °C only 0.0500 mol of the generic salt AB is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C?

Answer 1

no of moles of AB salt = 0.05 moles

volume of solution         = 1L

molarity of AB salt     = no of moles/volume in L

                                 = 0.05/1 = 0.05 M

    AB(s) --------------------> A^+ (aq) + B^- (aq)

                                         s                s

Ksp   = [A^+][B^-]

          = s^s

Ksp   = S^2

          = (0.05)^2    = 0.0025 >>>>>answer