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A mixture of KClO3 and KCl with a mass of 0.950 g was heated to produce...

A mixture of KClO3 and KCl with a mass of 0.950 g was heated to produce O2. After heating, the mass of residue was 0.660 g. Assuming all the KClO3 decomposed to KCl and O2, calculate the mass percent of KClO3 in the original mixture.

% KClO3

Solutions

Expert Solution

eqn: 2KClO3 ----> 2KCl + 3O2

moles of O2 lost = (0.950 g - 0.660g) / (MW O2 g/mole) = 0.29/32= 9.0625*10^-3 mol

g KClO3 = (2 moles KClO3/3 moles O2) * moles O2 * MW KClO3 (122.55 g/mole) = 0.74 g

% KClO3 = 100% * 0.74g KClO3 / 0.950 g = 77.94 %

queen_honey_blossom answered 2 years ago
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