Question

In: Chemistry

a group of five students attempted to estimate 100g of substance by balancing the amount of...

a group of five students attempted to estimate 100g of substance by balancing the amount of the substance with 100-g standard mass and obtained the following masses after each estimated amount weight: 95.8634g, 80.8125g, 106.5078g, 98.2865g, 86.4453g.

Create a data table as shown below and use the data to deteremine the answers for the following questions:

mass(g)    Deviation(g) % Deviation Error(g)    %    Error

a) 1. What is the mean?    2) What is the true value?

b) what are the deviation and % deviation from the mean for each value?

c) what are the error and % error for each value?

Solutions

Expert Solution

It has the average:

Mean = (95.8634 + 80.8125 + 106.5078 + 98.2865 + 86.4453) / 5 = 93.5831 g

You have the deviation:

SD = 10.1045 g

Deviation percentage is calculated:

% SD = SD * 100 / average = 10.1045 * 100 / 93.5831 = 10.80%

The error is calculated:

error = Actual value - Average value = 100 - 93.5831 = 6.4169 g

The error percentage is calculated:

% error = error * 100 / actual value = 6.4169 * 100/100 = 6.42%

If you liked the answer, please rate it positively, you would help me a lot, thanks.

It has the average:

Mean = (95.8634 + 80.8125 + 106.5078 + 98.2865 + 86.4453) / 5 = 93.5831 g

You have the deviation:

SD = 10.1045 g

Deviation percentage is calculated:

% SD = SD * 100 / average = 10.1045 * 100 / 93.5831 = 10.80%

The error is calculated:

error = Actual value - Average value = 100 - 93.5831 = 6.4169 g

The error percentage is calculated:

% error = error * 100 / actual value = 6.4169 * 100/100 = 6.42%

If you liked the answer, please rate it positively, you would help me a lot, thanks.


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