The scattered gamma rays from a source of 1332 keV have a distribution of energies as...

The scattered gamma rays from a source of 1332 keV have a distribution of energies as a function of the scattering angle q as follow:

E_g₀_- is the initial gamma energy, E_g_’ is the energy of the scattered gammaand, q is the scattering angle.

Do your calculation and choose the correct answer for the following:

The maximum energy of the scattered gamma, E_g_max
The maximum energy of the scattered electron, E_e-max
at what angle, q, you should stand to get an energy of 1000 keV

E_g-_max =1332 keV _, E_e-max =214 keV , q = 30⁰
E_g-_max =1332 keV _, E_e-max =214 keV , q = 60⁰
E_g-_max =1332 keV _, E_e-max =117.6 keV , q = 90⁰
None of the above

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genius_generous answered 1 year ago

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