Question

In: Physics

The scattered photon has an energy of 120 keV and the electron recoils with an energy...

The scattered photon has an energy of 120 keV and the electron recoils with an energy of 40 keV in Compton scattering.

Find:

(a) the incident photo wavelength

(b) the scattering angle of the photon

(c) the angle at which the electron recoils

Solutions

Expert Solution

given :

Energy of scattered photon = Es = 120 keV

Energy of electron = Ee = 40 keV

a) Assume wavelength of incident photon is .

From conservation of energy :

Energy of incident photon = Energy of scattered photon + Energy of electron

=> Energy of incident photon = Es + Ee = 120 + 40 = 160 keV.

Also, Energy of incident photon = . [h = Planck's constant, c = speed of light]

=> = hc / Energy of incident photon = [answer]

b) wavelength of scattered photon = = hc / Energy of scattered photon =

Compton shift formula is given by :

[where = wavelength of scattered photon, phi = angle of scattering of photon, mo = rest mass of electron]

[answer]

c) refer the diagram :

p = momentum of electron

theta = angle at which electron recoils

momentum of electron =

momentum of scattered photon =

Applying conservation of linear momentum along direction perpendicular to the incident photon :

Total final momentum along direction perpendicular to the incident photon = Total initial momentum along direction perpendicular to the incident photon

= 35.8 degree [answer]

genius_generous answered 1 year ago

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