In: Physics
The scattered photon has an energy of 120 keV and the electron recoils with an energy of 40 keV in Compton scattering.
Find:
(a) the incident photo wavelength
(b) the scattering angle of the photon
(c) the angle at which the electron recoils
given :
Energy of scattered photon = Es = 120 keV
Energy of electron = Ee = 40 keV
a) Assume wavelength of incident photon is .
From conservation of energy :
Energy of incident photon = Energy of scattered photon + Energy of electron
=> Energy of incident photon = Es + Ee = 120 + 40 = 160 keV.
Also, Energy of incident photon = . [h = Planck's constant, c = speed of light]
=> = hc / Energy of incident photon = [answer]
b) wavelength of scattered photon = = hc / Energy of scattered photon =
Compton shift formula is given by :
[where = wavelength of scattered photon, phi = angle of scattering of photon, mo = rest mass of electron]
[answer]
c) refer the diagram :
p = momentum of electron
theta = angle at which electron recoils
momentum of electron =
momentum of scattered photon =
Applying conservation of linear momentum along direction perpendicular to the incident photon :
Total final momentum along direction perpendicular to the incident photon = Total initial momentum along direction perpendicular to the incident photon
= 35.8 degree [answer]