Question

In: Chemistry

Use an ICE table to calculate the equilibrium amounts of all 3 chemicals if the initial...

Use an ICE table to calculate the equilibrium amounts of all 3 chemicals if the initial amounts are 0.20M of each.

Kc=1.59x102

Fe3+(aq)+SCN-(aq)-----> (Fe(SCN)2+)

Solutions

Expert Solution

               Kc = 1.59x102 = 159

                              Fe3+(aq) +   SCN-(aq)     ----->        Fe(SCN)2+

Initial                      0.2  M           0.2 M                              0.2 M

At equilibrium           0.2 -x          0.2 -x                              0.2 + x

              Kc = [Fe(SCN)2+] /[ Fe3+(aq)+] [SCN-(aq)]

     159 =   (0.2 + x) / (0.2 - x) (0.2 - x)

159 (x2- 0.4 x + 0.04 ) = 0.2 + x

159 x2- 63.6 x + 6.36 = 0.2 + x

159 x2- 64.6 x + 6.16 = 0

On solving,

   x = 0.153

Therefore,   equilibrium concentrations are

[ Fe3+(aq)+] = 0.2 - x = 0.2 - 0.153 = 0.047 M

[SCN-(aq)] = 0.2 - x = 0.2 - 0.153 = 0.047 M

[Fe(SCN)2+] = 0.2 + x = 0.2 + 0.153 = 0.353 M

  


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