A box of mass 8.0 kg is accelerated from rest across a floor at a rate...

A box of mass 8.0 kg is accelerated from rest across a floor at a rate of 6.0 m/s2 for 7.0 s . Find the net work done on the box.

Expert Solution

Solution :-

mass m = 8 kg

initial velocity u = 0

time t = 7 s

Acceration a = 6 m/s ²

From the relation v = u + at

= 0 +(7×6)

= 42 m/s

the net work done on the box W = Change in kinetic energy Since from work energy theorem

= (1/2)m[v ² - u ²]

= (1/2)(8)(42²)

= 7056 J

genius_generous answered 2 years ago

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