Question

In: Chemistry

As carried out in Section A, a 20 cm3 aliquot of a 0.0513 mol dm-3 vanadium(V)...

As carried out in Section A, a 20 cm3 aliquot of a 0.0513 mol dm-3 vanadium(V) solution wasreduced by excess zinc metal to an unknown oxidation state (x). The resulting lavender (lilac) coloured solution was then fully reoxidised by 32.3 cm3 of a 0.0199 mol dm-3 KMnO4solution.

Calculate the experimental value for the unknown oxidation state x (to two decimal places)

Solutions

Expert Solution

Concentration of V5+ = 0.0513 mol dm-3

Volume of aliquot = 20 cm3 = 0.02 dm3

Moles of V5+ = 0.0513 * 0.02

= 0.001026

Concentration of KMnO4 solution = 0.0199 mol dm-3

Volume of solution = 32.3 cm3 = 0.0323 dm3  

Moles of KMnO4 = 0.0199 * 0.0323

= 0.00064277

When V5+ is reduced to +x odidation state using Zn:

2V5+ + 2(5 - x)e- 2Vx+  

(5 - x)Zn     (5 - x)Zn2+   + 2(5 - x)e-
---------------------------------------------------------------
2V5+ +   (5 - x)Zn   2Vx+ + (5 - x)Zn2+

Now,

When Vx+ is odidized by KMnO4 solution.

3Vx+      3V5+ + 3(5 - x)e-

(5 - x)MnO4-  +   3(5 - x)e-     (5 - x)MnO2
---------------------------------------------------------------------------------------
3Vx+   +   (5 - x)MnO4-       3V5+ +   (5 - x)MnO2

As 3 moles Vx+ are oxidised by (5 - x) moles of KMnO4  

So, 0.001026 moles Vx+ will be oxidised by = ((5 - x) / 3) * 0.001026 moles of KMnO4  

But we have 0.00064277 moles of KMnO4

Therefore,

((5 - x) / 3) * 0.001026 = 0.00064277

(5 - x) * 0.001026 = 0.00192831

(5 - x) = 1.879

x = 5 - 1.879

x = 3.12


Related Solutions

As carried out in Section A, a 20 cm3 aliquot of a 0.0575 mol dm-3 vanadium(V)...
As carried out in Section A, a 20 cm3 aliquot of a 0.0575 mol dm-3 vanadium(V) solution wasreduced by excess zinc metal to an unknown oxidation state (x). The resulting lavender (lilac) coloured solution was then fully reoxidised by 32.5 cm3 of a 0.0199 mol dm-3 KMnO4solution. Calculate the experimental value for the unknown oxidation state x (to two decimal places)
A 20 cm3 aliquot of a 0.0577 mol dm-3 vanadium(V) solution wasreduced by iodide ions to...
A 20 cm3 aliquot of a 0.0577 mol dm-3 vanadium(V) solution wasreduced by iodide ions to an unknown oxidation state (x). The liberated iodine (I2) was titrated with 10.2 cm3 of a 0.0986 mol dm-3 Na2S2O3 solution. Calculate the experimental value for the unknown oxidation state x (to two decimal places).
3. Fluorine reacts with vanadium to produce vanadium(V) fluoride according to the following equation: 5 F2...
3. Fluorine reacts with vanadium to produce vanadium(V) fluoride according to the following equation: 5 F2 (g) + 2 V (s) → 2 VF5 (l) (a) How many moles of vanadium are needed to react completely with 0.1917 g of fluorine? (b) What is the maximum theoretical mass of vanadium(V) fluoride that can be produced? (c) If 0.225 g of vanadium(V) fluoride is obtained, what is the percent yield of VF5 (l)? Molar masses (g/mol): F2 38.00 VF5 145.93
The following experiment was carried out: 1.Prepare 250 cm3 of a solution of hydrogen peroxide by...
The following experiment was carried out: 1.Prepare 250 cm3 of a solution of hydrogen peroxide by adding 7.5 cm3 of the stock solution supplied to the volumetric flask and diluting to the required volume. 2. Pipette 25.0 cm3 of this solution into a conical flask. 3. Add 10 cm3 of 1 mol dm-3 sulphuric acid in a measuring cylinder. 4. Titrate the mixture against the potassium manganate (VII) until a permanent pale pink colour appears in the conical flask. 5....
a buffer solution is prepared by mixing 100cm3 aqueous NH3 0.1mol dm-3 with 100cm3 NH4Cl mol...
a buffer solution is prepared by mixing 100cm3 aqueous NH3 0.1mol dm-3 with 100cm3 NH4Cl mol dm-3 . Given that KB for NH3 =1.74x10^-5 ... 1) calculate pH of the buffer solution. ... 2)calculate the solution after addition 50cm3 HCl of 0.1 mol dm-3.
Tests were carried out on a three-phase 220 V, 50 Hz, 4-pole delta-connected induction motor. The...
Tests were carried out on a three-phase 220 V, 50 Hz, 4-pole delta-connected induction motor. The following results were obtained from open circuit (no-load) and short circuit tests.             Open Circuit (no-load) Test Applied Stator Voltage VLine (V) Stator Line Current ILine (A) Total Input Power Pin (W) 240 9.6 536 220 7.2 420 200 5.4 352 180 4.3 304 160 3.5 276 140 3.0 248 120 2.5 224             Short Circuit (locked rotor) Test Applied Stator Voltage VLine (V) Stator Line...
A titration is carried out using 20 mL of 0.500 M Formic Acid (1.8 x 10-4)...
A titration is carried out using 20 mL of 0.500 M Formic Acid (1.8 x 10-4) with 0.500 M NaOH. Calculate the pH after 10.0 mL, 20.0 mL, and 30.0 mL of NaOH have been added.
Out of a survey of 20 people 3 people said they do not like the taste...
Out of a survey of 20 people 3 people said they do not like the taste of cinnamon and 17 people said they liked the taste. For this sample, complete the following: a. Calculate the proportion who answered “yes” and the proportion who answered “no.” b. Calculate the 95% Confidence Interval for the proportion who answered “yes.” c. Using your survey results, test your hypothesis. Show work for all steps including the formulas. Calculate the p-value for the test. Use...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT