Let ?∈ℕ, and assume √? is irrational. Show that
ℚ(√?)={?+?√?∶?,?∈ℚ} is a field (show that there...
Let ?∈ℕ, and assume √? is irrational. Show that
ℚ(√?)={?+?√?∶?,?∈ℚ} is a field (show that there is multiplicative
commutativity and multiplicative inverse). What would change if ℚ
was replaced with ℝ.
Let a be a positive element in an ordered field. Show that if n
is an odd number, a has at most one nth root; if n is an
even number, a has at most two nth roots.
Let F be a vector field. Find the flux of F through the given
surface. Assume the surface S is oriented upward. F = eyi + exj +
24yk; S that portion of the plane x + y + z = 6 in the first
octant.
4. Use a proof by contradiction to show that the square root of
3 is irrational. You may use the following fact: For any integer k,
if k2 is a multiple of 3, then k is a multiple of 3. Hint: The
proof is very similar to the proof that √2 is irrational.
5. Use a direct proof to show that the product of a rational
number and an integer must be a rational number.
6. Use a proof by...
Let (F, <) be an ordered field, let S be a nonempty subset of
F, let c ∈ F, and for purposes of this problem let cS = {cx | x ∈
S}. (Do not use this notation outside this problem without defining
what you mean by the notation.) Assume that c > 0.
(i) Show that an element b ∈ F is an upper bound for S if and
only if cb is an upper bound for cS.
(ii)...
Prove the following:
(a) Let A be a ring and B be a field. Let f : A → B be a
surjective homomorphism from A to B. Then ker(f) is a maximal
ideal.
(b) If A/J is a field, then J is a maximal ideal.
Let R be a UFD and let F be a field of
fractions for R. If f(α) = 0, where
f ∈ R [x] is monic and α ∈
F, show that α ∈ R
NOTE: A corollary is the fact that m ∈
Z and m is not an nth
power in Z, then n√m is irrational.
1. Use cardinality to show that between any two rational numbers
there is an irrational number. Hint: Given rational numbers a <
b, first show that [a,b] is uncountable. Now use a proof by
contradiction.
2. Let X be any set. Show that X and P(X) do not have the same
cardinality. Here P(X) denote the power set of X. Hint: Use a proof
by contradiction. If a bijection:X→P(X)exists, use it to construct
a set Y ∈P(X) for which Y...