In: Statistics and Probability
Imagine you are the manager of a non-profit business, and you are looking to hire a recent college graduate. You list the position as paying $20,000/year. After interviewing candidates you decide that some will be offered the expected salary, while some will be offered more because of experience and interviewing skills. Others will be offered less than expected until they can demonstrate competence and their salary will increase when they are fully qualified.
Using Microsoft® Excel®, run a chi square Goodness of Fit test to determine whether these observed starting salaries are significantly different. What do the findings tell you?
Write a 75- to 100-word summary to describe your results.
Paste your Microsoft® Excel® output below your summary.
Expected Salaries |
Observed Salaries |
|
Applicant 1 |
$20,000 |
$17,500 |
Applicant 2 |
$20,000 |
$20,000 |
Applicant 3 |
$20,000 |
$22,000 |
Applicant 4 |
$20,000 |
$20,500 |
Applicant 5 |
$20,000 |
$20,000 |
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
H0:p1=0.2,p2=0.2,p3=0.2,p4=0.2,p5=0.2
Ha: Some of the population proportions differ from the values stated in the null hypothesis
This corresponds to a Chi-Square test for Goodness of Fit.
(2) Rejection Region
Based on the information provided, the significance level is α=0.05, the number of degrees of freedom is df=5−1=4, so then the rejection region for this test is R={χ2:χ2>9.488}.
(3) Test Statistics
The Chi-Squared statistic is computed as follows:
(4) Decision about the null hypothesis
Since it is observed that χ2=525>χc2=9.488, it is then concluded that the null hypothesis is rejected.
(5) Conclusion
It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the α=0.05 significance level.
Here is the excel input:
The output is:
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