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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance,...

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction

2COF2(g)⇌CO2(g)+CF4(g),    Kc=7.40

If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?

Where I get stuck is figuring out how to multiply (x)(x)/ (2.00-2x)^2 I know this is easy math but can you please work it out step for step so that I can see exactly how you go the answer.

Solutions

Expert Solution

                  2COF2(g)         ⇌            CO2(g)      +       CF4(g)

Initial                2                                0                          0

Change           -2x                              x                         x

equilubrium       2-2x                       x                              x

Kc=7.40 = (x)(x) / (2-2x)^2

7.4 = x2 / 4+4x2 -8x

29.6 + 29.6x2 -59.2x = x2

28.6x2 + 29.6 - 59.2x = 0

a = 28.6 , b = -59.2 c = 29.6

x = 59.2 - 10.88 / 2X 28.6 = 0.844

or x = 59.2 + 10.88 / 2X28.6 = 1.235 ( which is not possilbe, as 2x will then greater than 2)

So concentration of COF2 remained = 2-2X 0.844 = 0.312 M

queen_honey_blossom answered 3 weeks ago
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