In: Chemistry
Part A
1.Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction
2COF2(g)⇌CO2(g)+CF4(g), Kc=5.50
If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2remains at equilibrium?
Express your answer with the appropriate units.
Hints
|
|||
[COF2] = |
SubmitMy AnswersGive Up
Part B
Consider the reaction
CO(g)+NH3(g)⇌HCONH2(g), Kc=0.710
If a reaction vessel initially contains only CO and NH3 at concentrations of 1.00 M and 2.00 M, respectively, what will the concentration of HCONH2 be at equilibrium?
Express your answer with the appropriate units.
Hints
|
|||
[HCONH2] = |
SubmitMy AnswersGive Up.
Part A
What is the equilibrium concentration of CO at 1000 K?
Express your answer in molarity to three significant figures.
|
||||
[CO] = | M |
SubmitMy AnswersGive Up
Part B
What is the equilibrium concentration of Cl2 at 1000 K?
Express your answer in molarity to three significant figures.
|
||||
[Cl2] = | M |
SubmitMy AnswersGive Up
Part C
What is the equilibrium concentration of COCl2 at 1000 K?
Express your answer in molarity to three significant figures.
|
||||
[COCl2] = | M |
SubmitMy AnswersGive Up
2COF2(g)⇌CO2(g)+CF4(g),
I 2 0 0
C -2x x x
E 2-2x +x +x
Kc = [CO2][CF4]/[COF2]^2
5.5 = x*x/(2-2x)^2
5.5*(2-2x)^2 = x^2
x = 0.82
[COF2] = 2-2x = 2-2*0.82 = 0.36M
[CO2] = x = 0.82M
[CF4] = x = 0.82M
part-B
CO(g)+NH3(g)⇌HCONH2(g),
I 1 2 0
C -x -x +x
E 1-x 2-x +x
Kc = [HCONH2]/[CO][Nh3]
0.71 = x/(1-x)(2-x)
0.71*(1-x)(2-x) = x
x = 0.513
[CO] = 1-x = 1-0.513 = 0.487M
[NH3] = 2-x = 2-0.513 = 1.487M
[HCONH2] = x= 0.513M