In: Statistics and Probability
A poll conducted by the Shire Institute for Statistical Research discovered that only 39% of 164 randomly sampled inhabitants of the West Farthing enjoy boating on the Brandywine River, while the same poll discovered that 53% of 143 randomly sampled inhabitants of Buckland enjoy this activity. Perform a significance test at α = 0.05 to determine if the proportion of Hobbits in the West Farthing who enjoy boating is significantly lower than the proportion of Hobbits in Buckland who do.
10.1 Provide the hypotheses for this test:
10.2 Provide the value for p̂pooled:
10.3 Provide the value of the numerator of the test statistic:
10.4 Provide the value of the denominator of the test statistic:
10.5 Provide the final answer of the test statistic:
10.6 Provide the p-value:
10.7 Provide the comparison needed to make the conclusion:
10.8 Provide the conclusion for the test:
Two sample proportion test (z-test)
Aim: determine if the proportion of Hobbits in the West Farthing who enjoy boating is significantly lower than the proportion of Hobbits in Buckland who do.
Given: two samples : West Farthing and Buckland
Sample 1: sample size (n1)= 164
Proportion (p1) = the proportion of Hobbits in the West Farthing who enjoy boating
P1 =39% = 0.39
Sample 2: sample size (n2)=143
Proportion (p2)= the proportion of Hobbits in the Buckland who enjoy boating
P2= 53% = 0.53
10.1Hypothesis
Null Hypothesis (H0) : p1 = p2
i.e. there is no significant difference between proportions of Hobbits the West Farthing and in
the Buckland who enjoy boating
Alternative Hypothesis (H1) : p1 < p2
i.e. the proportion of Hobbits in the West Farthing who enjoy boating is significantly lower than the proportion of Hobbits in Buckland who do
10.2 p̂pooled =ppooled
p = (p1 * n1 + p2 * n2) / (n1 + n2)
p= (0.39*164+0.53*143)/(164+143)
p= 0.455212
10.3 the numerator of the test statistic:
Numerator = p1-p2 =0.39-0.53= -0.14
10.4 the denominator of the test statistic:
SE = sqrt{ p * ( 1 - p ) * ( (1/n1) + (1/n2) ) }
SE= sqrt {0.4552*(1-0.4552)*((1/164)+(1/143)))
SE= 0.056977
10.5 the test statistic:
Test statistic z= (p1-p2)/SE= -2.45713
10.6 the p-value: 0.0070
(From EXCEL : =NORM.S.DIST(z,TRUE)
10.7 the conclusion: Here p-value = 0.007 < alpha =0.05. therefore we reject H0.
10.8 the conclusion for the test: the proportion of Hobbits in the West Farthing who enjoy boating is significantly lower than the proportion of Hobbits in Buckland who do