Question

In: Civil Engineering

VISCOSITY OF FLUID

A liquid (ρ = 1000 kg/m3; μ = 2 × 10–2 N ∙ s/m2; v = 2 × 10–5 m2/s) flows tangentially past a flat plate with total length of 4 m (parallel to the flow direction), a velocity of 1 m/s, and a width of 1.5 m. What is the skin friction drag (shear force) on one side of the plate?

Solutions

Expert Solution

Newton law : Shear stress is directly proportional to shear strain. Fluids which obeys the Newtons law called newtonion fluid

Density of fluid = 1000 kg/m3

Velosity of fluid = 1m/s

Kinematic viscosity = 2x10^-2

Distance between plates = 1.5

We know Shear Stress = dynamic viscosity x (velosity/distance between plates)

 Shear stress = 20x1/1.5

                          = 13.33333N/m2

 

 

 

 

 

 

 

 

 

 

 

 

 

Shear Force = shear stress / area

Shear Force = 80N

KOTTE VINAY VARDHAN answered 2 years ago
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