At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, Kc. 3A(g)...

At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, Kc.
3A(g) + 2B(g) <------> 4C(g)
Kc= 3.13x 10^31

If, at this temperature, 1.90 mol of A and 4.00 mol of B are placed in a 1.00-L container, what are the concentrations of A, B, and C at equilibrium?

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Expert Solution

Initial 1.90 4 0

Final (1.90-3x) 2x 4x

solve for x, it will be close to 0.63

Hence the final concentration will be

C = 4 * 0.6328 = 2.5312 moles

B = 4 - 2 * 0.6328 = 2.73 moles

A = 1.90 - 3 * 0.6328 = 0.0016 moles

queen_honey_blossom answered 1 year ago

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