Question
In: Chemistry
Aluminum chloride, AlCl3, is made by treating scrap aluminum with chlorine. 2 Al (s) + 3...
Aluminum chloride, AlCl3, is made by treating scrap aluminum with chlorine. 2 Al (s) + 3 Cl2 (g) → 2 AlCl3 (s). If you begin with 6.73 g of aluminum and 31.43 g of chlorine,
(a) Which reactant is the limiting reagent?
(b) What mass of AlCl3 can be produced?
(c) What mass of excess reactant remains when the reaction is completed?
Solutions
queen_honey_blossom answered 2 years agoRelated Solutions
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2 Al +...
Aluminum reacts with chlorine gas to form aluminum chloride via
the following reaction:
2 Al + 3 Cl2 → 2 AlCl3
How many grams of aluminum chloride could be produced from 34.00
g of aluminum and 39.00 g of chlorine gas? How much of the excess
reactant will be left after the reaction has gone to completion?
(Al = 26.98 amu, Cl = 35.45 amu)
Mass of product = Blank 1 grams of AlCl3
Mass of excess reactant remaining =...
Aluminum chloride is made from aluminum metal and chlorine gas, as shown: 2Al(s) + 3Cl2(g) --->...
Aluminum chloride is made from aluminum metal and chlorine gas,
as shown:
2Al(s) + 3Cl2(g) ---> 2AlCl3(s)
When 10.0g of aluminum and 25.0g of chlorine are reacted, 18.6g
of aluminum chloride is formed. Determine:
a) the limiting reactant
b) the theoretical yield in grams
c) the percent yield for this reaction
d) the excess reactant in grams
Aluminum chloride, AlCl3, is an inexpensive reagent used in many industrial processes. It is made by...
Aluminum chloride, AlCl3, is an inexpensive reagent used in many
industrial processes. It is made by treating scrap aluminum with
chlorine gas according to the following balanced chemical
equations:
2 Al (s) + 3 Cl2 (g) = 2 AlCl (s)
If you start with 5.60 g of Al and 3.25 g of Cl2, how much
aluminum chloride should be formed? What is the limiting reactant
in this situation?
Q1)Aluminum reacts with chlorine gas to form aluminum chloride. 2Al(s)+3Cl2(g)→2AlCl3(s).What minimum volume of chlorine gas (at...
Q1)Aluminum reacts with chlorine gas to form aluminum chloride.
2Al(s)+3Cl2(g)→2AlCl3(s).What
minimum volume of chlorine gas (at 298 K and 229 mmHg ) is required
to completely react with 8.60 g of aluminum? please explain the
step, how you got to the answer for this problem.
A)38.8 mL
B)38.8 L
C)388 L
D)0.388 L
Q2)Calculate the density of oxygen, O2 under each of the
following conditions
STP and 1.00atm and 35.0 Celcius
(Express answer numerically in grams per liter. Enter density...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is...
Aluminum reacts with chlorine gas to form aluminum chloride via
the following reaction:
2Al(s)+3Cl2(g)→2AlCl3(s)
What is the maximum mass of aluminum chloride that can be formed
when reacting 26.0 g of aluminum with 31.0 g of chlorine?
Express your answer to three significant figures and include the
appropriate units.
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is...
Aluminum reacts with chlorine gas to form aluminum chloride via
the following reaction:
2Al(s)+3Cl2(g)→2AlCl3(s)
What is the maximum mass of aluminum chloride that can be formed
when reacting 15.0g of aluminum with 20.0 g of chlorine?
Consider the following reaction: 2 Al + 3 CuCl2 → 3 Cu + 2 AlCl3 The...
Consider the following reaction:
2 Al + 3 CuCl2 → 3 Cu + 2 AlCl3
The reaction begins with 83.16 g of Al and 49.19 g of copper II
chloride.
How much of the excess reactant is left behind
(unused)? g
How many grams of Cu is produced: g
How many grams of AlCl3 is produced: g
Calculate the standard enthalpy of formation of solid AlCl3 from the following data: 2 Al(s) +...
Calculate the standard enthalpy of formation of solid
AlCl3 from the following data:
2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3
H2(g)
ΔHo = -1048 kJ
HCl(aq) → HCl(g)
ΔHo = 75 kJ
Cl2(g) + H2(g) → 2 HCl(g)
ΔHo = -186 kJ
AlCl3(s) →
AlCl3(aq)
ΔHo = -323 kJ
ZnCl2 (aq) + Al (s) ---- Zn(s) + AlCl3 (aq) [Al3+] = 0.8 M [Zn2+] =...
ZnCl2 (aq) + Al (s) ---- Zn(s) + AlCl3 (aq)
[Al3+] = 0.8 M [Zn2+] = 1.3M
Zn2+(aq) +2e- ---Zn(s) -0.76V
Al3+(aq) + 3e- --- Al (s) -1.66V
Balance the equation above.
Give the equation for the reaction quotient(Q) and solve for it.
Are there units for (Q)?
Solve for the standard potential for the cell (EO cell) at 295K.
First give equation.
Solve the Nernst equation for this cell at 295K.
Al(OH)3(s) + HCl(aq) --> AlCl3(aq) + H2O(I) a) balance the equation b)calculate the number of grams...
Al(OH)3(s) + HCl(aq) --> AlCl3(aq) + H2O(I) a) balance the
equation b)calculate the number of grams s of HCl that can reacct
with 0.500 g of Al(OH)3. c) calculate the number of AlCl3 and the
number of grams of H2O formed when 0.500g of Al(OH)3 reacts. d)
show that your calculations from parts b and c are consistent with
the law of conservation of mass.
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