Question

In: Physics

GOAL Apply the more general definition of torque. PROBLEM (a) A man applies a force of...

GOAL Apply the more general definition of torque. PROBLEM (a) A man applies a force of F = 3.00 102 N at an angle of 60.0° to the door of Figure (a), 2.00 m from the hinges. Find the torque on the door, choosing the position of the hinges as the axis of rotation. (b) Suppose a wedge is placed 1.50 m from the hinges on the other side of the door. What minimum force must the wedge exert so that the force applied in part (a) won't open the door? STRATEGY Part (a) can be solved by substitution into the general torque equation. In part (b) the hinges, the wedge, and the applied force all exert torques on the door. The door doesn't open, so the sum of these torques must be zero, a condition that can be used to find the wedge force. SOLUTION (A) Compute the torque due to the applied force exerted at 60.0°. Substitute into the general torque equation. τF = rFsin θ = (2.00 m)(3.00 ✕ 102 N) sin 60.0° = (2.00 m)(2.60 ✕ 102 N) = 5.20 102 N · m (B) Calculate the force exerted by the wedge on the other side of the door. Set the sum of the torques equal to zero. τhinge + τwedge + τF = 0 The hinge force provides no torque because it acts at the axis (r = 0). The wedge force acts at an angle of −90.0°, opposite the upward 260 N component. 0 + Fwedge(1.50 m) sin (−90.0°) + 5.20 ✕ 102 N · m = 0 Fwedge = 347 N LEARN MORE REMARKS Notice that the angle from the position vector to the wedge force is −90°. This is because, starting at the position vector, it's necessary to go 90° clockwise (the negative angular direction) to get to the force vector. Measuring the angle in this way automatically supplies the correct sign for the torque term and is consistent with the right-hand rule. Alternately, the magnitude of the torque can be found and the correct sign chosen based on physical intuition. Figure (b) illustrates the fact that the component of the force perpendicular to the lever arm causes the torque. QUESTION To make the wedge more effective in keeping the door closed, should it be placed closer to the hinge or to the doorknob? closer to the hinge closer to the doorknob PRACTICE IT Use the worked example above to help you solve this problem. (a) A man applies a force of F = 3.00 102 N at an angle of 60.0° to a door, x = 2.10 m from the hinges. Find the torque on the door, choosing the position of the hinges as the axis of rotation. N · m (b) Suppose a wedge is placed 1.50 m from the hinges on the other side of the door. What minimum force must the wedge exert so that the force applied in part (a) won't open the door? N EXERCISE HINTS: GETTING STARTED | I'M STUCK! A man ties one end of a strong rope 7.74 m long to the bumper of his truck, 0.521 m from the ground, and the other end to a vertical tree trunk at a height of 3.62 m. He uses the truck to create a tension of 7.50 102 N in the rope. Compute the magnitude of the torque on the tree due to the tension in the rope, with the base of the tree acting as the reference point. N · m

Solutions

Expert Solution

Given that :

applied force, F = 3 x 102 N = 300 N

angle, = 60 degree

distance from the hinges, r = 2 m

(a) The torque on the door, choosing the position of the hinges as the axis of rotation which is given as :

using an equation,      = r F sin

= (2 m) (300 N) sin 600

= (600 Nm) (0.866)

= 519.6 Nm

= 5.2 x 102 Nm

(b) Suppose, a wedge is placed 1.5 m from the hinges on the other side of the door. The minimum force exerted by the wedge so that the force applied in part (a) won't open the door which given as :

using an equation, we have

hinge + wedge + F = 0

then, we have

0 + (1.5 m) Fwedge sin (-90)0 + (5.2 x 102 Nm) = 0

(1.5 m) Fwedge = (5.2 x 102 Nm)

Fwedge = (5.2 x 102 Nm) / (1.5 m)

Fwedge = 347 N


Related Solutions

The formula for a particular solution given in (3.42) applies to the more general problem of...
The formula for a particular solution given in (3.42) applies to the more general problem of solving y" + p(t)y' + q(t)y = f(t). In this case, y1 and y2 are independent solutions of the associated homogeneous equation y" + p(t)y' + q(t)y = 0. In the following, show that y1 and y2 satisfy the associated homogeneous equation, and then determine a particular solution of the inhomogeneous equation: b.) ty" - (t + 1)y' + y = t2e2t; y1(t) =...
Give a more general expression for the magnitude of the torque T. Rewrite the answer found in Part A in terms of the magnitude of the magnetic dipole moment of the current loop m.
Give a more general expression for the magnitude of the torque T. Rewrite the answer found in Part A in terms of the magnitude of the magnetic dipole moment of the current loop m. Define the angle between the vector perpendicular to the plane of the coil and the magnetic field to be ф, noting that this angle is the complement of angle θ in Part A. Give your answer in terms of the magnetic moment m, magnetic field B, and...
Principles of Finance (FINC 311) Homework Assignment 2 Learning Goal 1: Analytical - Apply appropriate problem-solving...
Principles of Finance (FINC 311) Homework Assignment 2 Learning Goal 1: Analytical - Apply appropriate problem-solving methodologies to the analysis and solution of financial problems Students are able to use TVM techniques to problems involving loan payments and asset values Student computes present and future values 1.                           a.             You deposit $100 into an account earning a 10% annual rate of interest. How much money will you have in the account at the end of five years?                 b.             You...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT