Question

A woodpecker's brain is specially protected from large decelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.565 m/s in a distance of only 2.15 mm.

a. Find the acceleration in m/s2 and

b. Find the acceleration in multiples of g (g = 9.80 m/s2)

c. Calculate the stopping time (in s).

Part d: The tendons cradling the brain stretch, making its stopping distance 4.05 mm (greater than the head and, hence, less deceleration of the brain). What is the brain's deceleration, expressed in multiples of g?

Answer 1

PART (a):

Given that:

Initial speed, u = 0.565 m/s

Final speed, v = 0 m/s

Stopping distance, s = 2.15 mm = 2.15 x 10^-3 m

Therefore, acceleration is given by:

Negative sign indicates deceleration.

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PART (b):

Given that, g = 9.80 m/s²

Therefore, a = (-74.24) / (9.8) = -7.58 g ------- (**Answer**)

(Again, negative sign indicates deceleration)

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PART (c):

Stopping time is given by:

or

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PART (d):

Given that:

Initial speed, u = 0.565 m/s

Final speed, v = 0 m/s

Stopping distance, s = 4.05 mm = 4.05 x 10^-3 m

Therefore, acceleration is given by:

Negative sign indicates deceleration.

In multiples of g:

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