Question

In: Physics

A 0.600 kg block is attached to a spring with spring constant 18.0 N/m . While...

A 0.600 kg block is attached to a spring with spring constant 18.0 N/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 40.0 cm/s . What is the block's speed at the point where x= 0.550 A?

Expert Solution

Mass of bloc m = 0.6 kg

Spring constant k = 18 N/m

Speed V = 40 cm/s

A = 0.4 m/s -------------( 1)

Displacment x = 0.55 A

The block's speed at the point where x= 0.550 A is v = [A ² - x ² ]

= [A ² -(0.55A) ²]

= [A ² -0.3025 A ²]

= [0.6975 A ²]

= (0.8351 A)

= 0.8351 A

= 0.8351 (0.4 m/s) Since from equation(1)

= 0.334 m/s

= 33.4 cm/s

genius_generous answered 3 days ago

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