Sketch the region enclosed by the given curves. Decide whether
to integrate with respect to x...
Sketch the region enclosed by the given curves. Decide whether
to integrate with respect to x or y. Draw a typical approximating
rectangle. y = 2 + 2 sqrt(x) , y = (6 + x) / 3
Solutions
Expert Solution
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Sketch the region enclosed by the given curves. Decide whether
to integrate with respect to x or y. Draw a
typical approximating rectangle.
y =
2/x, y =
2/x2, x =
7
And also find the area
Sketch the region enclosed by the given curves.
y = 8 cos
8x, y = 8 − 8 cos
8x, 0 ≤ x ≤
π/6
I already have the sketch however I need its Area
A) Find its area
Sketch the region in the first quadrant enclosed by y=2/x ,
y=3x, and y=1/3x. Decide whether to integrate with respect to x or
y. Then find the area of the region.
Area =
Find the area of the region enclosed between y=4sin(x) and
y=2cos(x) from x=0 to x=0.4π
Hint: Notice that this region consists of two parts.
1.Sketch the region enclosed by the graphs of each of the
following curves, and determine the area of the region enclosed by
the graphs of the functions:
y=x^2
y=4x-x^2
2. Find the area between the graph of and the x axis
on the interval [-3, 1].
Consider the region R enclosed between the curves y = 2 /x and y
= 1, between x = 1 and x = 2.
Calculate the volume of the solid obtained by revolving R about
the x-axis,
(a) using cylindrical shells;
(b) using washers
a. Find the volume of the solid obtained by rotating the region
enclosed by the curves y = 4 x^2 , y = 5 − x^2 about the line y =
11
b. Find the volume of the solid obtained by rotating the region
enclosed by the graphs about the given axis.
y = 2sqt (x), y=x, about x=-20.
Please leave your answer in fraction if
possble