A 460 turn solenoid, 25 cm long, has a diameter of 2.2 cm. A short 2.6...

A 460 turn solenoid, 25 cm long, has a diameter of 2.2 cm. A short 2.6 cm diameter 12 turn coil is wound around the solenoid at its midpoint. What rate of change of current in the solenoid, will cause a 220

Expert Solution

Given that number of turns is N = 600
Length of the solenoid is L = 24 cm
diameter is d = 2.7 cm
radius of the coil is r = 1.35cm
Area of the coil is A = ?r^2
                                = ? ( 1.1*10^-2m)^2
                                = 3.80*10^-4 m^2
magnetic field is B = ?_0 n I
    n = N_1 / L
       = 460 / 25 *10^-2 m
       = 1840 turns / m
the induced emf   ? = N d ? / dt
                           220 x10-6      = 12 * B* 3.80*10^-4 m^2 / t
B/t =0.0482

B /t = 4?*10^-7 * 1840 * i/t
i/t = 0.0482 / ( 4xpi x 10-7 x 1840)
i/t = 20.87

genius_generous answered 1 month ago

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