In: Chemistry
Use standard free energies of formation to calculate ΔG∘ at 25∘C for each of the following reactions.
1. CoO(s)+H2(g)→Co(s)+H2O(g)
2. NH4I(s)→HI(g)+NH3(g)
3.H2(g)+FeO(s)→Fe(s)+H2O(g)
4.SiH4(g)→Si(s)+2H2(g)
ΔG0 = ∑ΔG0f (Products) - ∑ΔG0f (reactants)
Using this formula,
1) CoO(s) + H2(g) ---------> Co(s) + H2O(g)
ΔG0 = [ΔG0f Co (s) + ΔG0f (H2O)] – [ΔG0f CoO (s) + ΔG0f H2 (g)]
ΔG0 = [(0) + (-228.61)] – [(-214.2) + (0)]
ΔG0 = -14.41 kJ
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2) NH4I(s)→HI(g)+NH3(g)
ΔG0 = [ΔG0f HI (g) + ΔG0f (NH3 (g))] – [ΔG0f NH4I (g)]
ΔG0 = [(+1.3) + (-13.4)] – [-112 ]
ΔG0 = + 99.9 kJ [or + 100 KJ ]
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3) H2(g)+FeO(s)→Fe(s)+H2O(g)
ΔG0 = [ΔG0f Fe (s) + ΔG0f (H2O)] – [ΔG0f FeO (s) + ΔG0f H2 (g)]
ΔG0 = [(0) + (-228.61)] – [(−251.4) + (0)]
ΔG0 = + 22.79 kJ [or + 22.8 KJ]
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4) SiH4(g)→Si(s)+2H2(g)
ΔG0 = [ΔG0f Si(s) + 2 ΔG0f H2(g) ] – [ΔG0f SiH4(g)]
ΔG0 = [ 0 + 2 x (0 )] – [+ 56.9]
ΔG0 = - 56.9 kJ [or + 57 KJ]
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