Expand in Fourier series: f(x) = x|x|, -L<x<L, L>0 f(x) = cosx(sinx)^2 , -pi<x<pi f(x) =...

Expand in Fourier series:

f(x) = x|x|, -L<x<L, L>0

f(x) = cosx(sinx)^2 , -pi<x<pi

f(x) = (sinx)^3, -pi<x<pi

Expert Solution

fourier coefficient s are zero in the derivation due to function criteria and somewhere by easy calculation.

Colby Messinger answered 2 years ago

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