Question

Multiples of 2 and 3: write a c++ program Using a while loop, write a program that reads 10 integer numbers. The program shall count how many of them are multiples of 2, how many are multiples of 3, and how many are NOT multiples of either 2 or 3. The output should be similar to the one shown below.

Answer 1

All the explanations is given in the comments of the code itself.

Code--

#include<bits/stdc++.h>
using namespace std;
int main()
{
   int x,m2,m3,nm;
   int i=0;
   m2=0;
   m3=0;
   nm=0;
   //run a loop 10 times
   while(i<10)
   {
       //prompt the user to enter a number
       cout<<"Enter a number: ";
       cin>>x;
      
       //check if the number is multiple of 2
       if(x%2==0)
       {
           //increament m2 by 1
           m2=m2+1;
       }
       //check if the number is multiple of 3
       if(x%3==0)
       {
           //increament m2 by 1
           m3=m3+1;
       }
       //if not multiples of either 2 or 3
       if((x%2!=0)||(x%3!=0))
       {
           //increament nm by 1
           nm=nm+1;
       }
       i++;
   }
   //display the output
   cout<<endl<<"Multiples of 2 = "<<m2<<endl;
   cout<<"Multiples of 3 = "<<m3<<endl;
   cout<<"Not Multiples of 2 or 3 = "<<nm<<endl;
}

Code Screenshot--

Output Screenshot--

Note--

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