An electron has an initial velocity of (12.0j + 15.0k) km/s and a constant acceleration of...

An electron has an initial velocity of (12.0j + 15.0k) km/s and a constant acceleration of (2.00*10^12 i) m/s^2 in a region in which uniform electric and magentic fields are present. If B=(400*10^-6 i)T, find the electric field

Expert Solution

The net force acting on the electron is equal to sum of theforces acting on the electron due to both electric field andmagnetic field's.i.e.,
F_net = F_mag +F_ele.
ma = (Bv)q + Eq
Where m = mass of the electron = 9.1*10^-31kg.
           a = acceleration of the electron. = (2,00 x 10^12 m/s)i.
           B = Magnetic field induction = (400uT)i.
           q = charge of the electron.= 1.6*10^-19 col.
           v = velocity of the electron.= (12.0j +15.0k)km/s
           E = Electric field intensity.
therefore ma = q[(Bv)+E].
               (Bv)+E = ma/q
                       E = (ma/q) - (Bv).
Substitute the values in the in the above equation to find 'E'.

genius_generous answered 1 month ago

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