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You are to prepare 100 mL of a pH 3.76 buffer solution with a formal concentration...

You are to prepare 100 mL of a pH 3.76 buffer solution with a formal concentration of 0.0500 F (i.e., total concentration of all acetate species is 0.0500 M). Calculate how many grams, of acetic acid and sodium acetate mix together.

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Expert Solution

Solution :-

Volume of solution = 100 ml = 0.100 L

Total concentration = 0.0500 M

Total moles = 0.0500 mol per L * 0.100 L = .0.00500 mol

Now lets calculate the ratio of the conjugate base to acid

pH= pka + log ( [conj base]/[acid])

3.76 = 4.74 + log ( [conj base]/[acid])

3.76 -4.74 = log ( [conj base]/[acid])

-0.98 = log ( [conj base]/[acid])

Antilog [-0.98] = conj base / acid

0.1047 = conj base / acid

Now lets calculate the moles of the conjugate base

0.1047 * 0.005 mol = 0.0005235 mol conjugate base (sodium acitate)

Moles of acetic acid = 0.00500 mol – 0.0005235 mol = 0.004476 mol

Now lets calculate the mass of each

Mass of sodium acetate = moles * molar mass

                                              = 0.0005235 mol * 82.0343 g per mol

                                             = 0.0429 g sodium acetate

Mass of acetic acid = moles * molar mass

                              = 0.004476 mol * 60.05 g per mol

                              = 0.2688 g acetic acid

queen_honey_blossom answered 2 years ago
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