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prepare a 100 ml of pH 10 Buffer solution using NH4Cl (s) and concentrated NH4OH ,...

prepare a 100 ml of pH 10 Buffer solution using NH4Cl (s) and concentrated NH4OH , the NH4OH molartiy is 18.1 M ? NH4OH is equal to NH3 (aq)

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Expert Solution

PH = 10

POH = 14-PH

           = 14-10 = 4

[NH3] = 18.1M

POH = Pkb + log[NH4Cl]/[NH3]

4       = 4.75 + log[NH4Cl]/18.1

4-4.75    = log[NH4Cl]/18.1

log[NH4Cl]/18.1   = -0.75

   [NH4Cl]/18.1    = 10^-0.75

[NH4Cl]/18.1         = 0.178

        [NH4Cl]       = 0.178*18.1 = 3.2218M

     no of moles of NH4Cl   = molarity * volume in L

                                         = 3.2218*0.1   = 0.32218moles

mass of NH4Cl               = no of moles * gram molar mass

                                        = 0.32218*53.5   = 17.24g

queen_honey_blossom answered 1 year ago
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