Question

find the broadcast address for 10.248.139.232 with mask 255.255.255.252

Answer 1

Answer:
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10.248.139.235

Explanation:
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IP Address: 10.248.139.232
----------------------------------------
Let's first convert this into binary format
10.248.139.232
Let's convert all octets to binary separately
Converting 10 to binary
Divide 10 successively by 2 until the quotient is 0
   > 10/2 = 5, remainder is 0
   > 5/2 = 2, remainder is 1
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 1010
So, 10 of decimal is 1010 in binary
10 in binary is 00001010

Converting 248 to binary
Divide 248 successively by 2 until the quotient is 0
   > 248/2 = 124, remainder is 0
   > 124/2 = 62, remainder is 0
   > 62/2 = 31, remainder is 0
   > 31/2 = 15, remainder is 1
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111000
So, 248 of decimal is 11111000 in binary
248 in binary is 11111000

Converting 139 to binary
Divide 139 successively by 2 until the quotient is 0
   > 139/2 = 69, remainder is 1
   > 69/2 = 34, remainder is 1
   > 34/2 = 17, remainder is 0
   > 17/2 = 8, remainder is 1
   > 8/2 = 4, remainder is 0
   > 4/2 = 2, remainder is 0
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10001011
So, 139 of decimal is 10001011 in binary
139 in binary is 10001011

Converting 232 to binary
Divide 232 successively by 2 until the quotient is 0
   > 232/2 = 116, remainder is 0
   > 116/2 = 58, remainder is 0
   > 58/2 = 29, remainder is 0
   > 29/2 = 14, remainder is 1
   > 14/2 = 7, remainder is 0
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11101000
So, 232 of decimal is 11101000 in binary
232 in binary is 11101000

=====================================================================================
||    10.248.139.232 in binary notation is 00001010.11111000.10001011.11101000    ||
=====================================================================================

Subnet address: 255.255.255.252
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Let's convert this into binary format
255.255.255.252
Let's convert all octets to binary separately
Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
   > 255/2 = 127, remainder is 1
   > 127/2 = 63, remainder is 1
   > 63/2 = 31, remainder is 1
   > 31/2 = 15, remainder is 1
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
So, 255 of decimal is 11111111 in binary
255 in binary is 11111111

Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
   > 255/2 = 127, remainder is 1
   > 127/2 = 63, remainder is 1
   > 63/2 = 31, remainder is 1
   > 31/2 = 15, remainder is 1
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
So, 255 of decimal is 11111111 in binary
255 in binary is 11111111

Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
   > 255/2 = 127, remainder is 1
   > 127/2 = 63, remainder is 1
   > 63/2 = 31, remainder is 1
   > 31/2 = 15, remainder is 1
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
So, 255 of decimal is 11111111 in binary
255 in binary is 11111111

Converting 252 to binary
Divide 252 successively by 2 until the quotient is 0
   > 252/2 = 126, remainder is 0
   > 126/2 = 63, remainder is 0
   > 63/2 = 31, remainder is 1
   > 31/2 = 15, remainder is 1
   > 15/2 = 7, remainder is 1
   > 7/2 = 3, remainder is 1
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111100
So, 252 of decimal is 11111100 in binary
252 in binary is 11111100

======================================================================================
||    255.255.255.252 in binary notation is 11111111.11111111.11111111.11111100    ||
======================================================================================

Remove all dots to form 11111111111111111111111111111100
Remove all 0's from the right side to form 111111111111111111111111111111
Number of 1's in this is 30
so, Subnet mask is /30

For Calculating broadcast ID, keep first 30 bits of 00001010.11111000.10001011.11101000 and set all remaining bits to 1.
so, broadcast ID in binary is 00001010.11111000.10001011.11101011
00001010.11111000.10001011.11101011:
----------------------------------------
00001010.11111000.10001011.11101011
Let's convert all octets to decimal separately
Converting 00001010 to decimal
Converting 00001010 to decimal
00001010
=> 0x2^7+0x2^6+0x2^5+0x2^4+1x2^3+0x2^2+1x2^1+0x2^0
=> 0x128+0x64+0x32+0x16+1x8+0x4+1x2+0x1
=> 0+0+0+0+8+0+2+0
=> 10
00001010 in decimal is 10

Converting 11111000 to decimal
Converting 11111000 to decimal
11111000
=> 1x2^7+1x2^6+1x2^5+1x2^4+1x2^3+0x2^2+0x2^1+0x2^0
=> 1x128+1x64+1x32+1x16+1x8+0x4+0x2+0x1
=> 128+64+32+16+8+0+0+0
=> 248
11111000 in decimal is 248

Converting 10001011 to decimal
Converting 10001011 to decimal
10001011
=> 1x2^7+0x2^6+0x2^5+0x2^4+1x2^3+0x2^2+1x2^1+1x2^0
=> 1x128+0x64+0x32+0x16+1x8+0x4+1x2+1x1
=> 128+0+0+0+8+0+2+1
=> 139
10001011 in decimal is 139

Converting 11101011 to decimal
Converting 11101011 to decimal
11101011
=> 1x2^7+1x2^6+1x2^5+0x2^4+1x2^3+0x2^2+1x2^1+1x2^0
=> 1x128+1x64+1x32+0x16+1x8+0x4+1x2+1x1
=> 128+64+32+0+8+0+2+1
=> 235
11101011 in decimal is 235

======================================================================================
||    00001010.11111000.10001011.11101011 in decimal notation is 10.248.139.235    ||
======================================================================================
===============================================
||    So, broadcast ID is 10.248.139.235    ||
===============================================