Find the network ip and broadcast ip of the ip address: 192.168.225.212/27

Expert Solution

subnetmask = 27 ones followed by 4 zeros in binary
           = 11111111.11111111.11111111.11100000
           = 255.255.255.224

Network = Ip address AND subnet mask
        = 192.168.225.212 AND 255.255.255.224
192.168.225.212 in binary is 11000000.10101000.11100001.11010100
255.255.255.224 in binary is 11111111.11111111.11111111.11100000
So, Network in binary is 11000000.10101000.11100001.11000000
So, Network in decimal is 192.168.225.192

network ip: 192.168.225.192

==============================
Wildcard = Inverse of netmask
         = 00000000.00000000.00000000.00011111 (In binary)
         = 0.0.0.31 (In decimal)

Broadcast = IP address || Wildcard
          = 192.168.225.212 AND 0.0.0.31

192.168.225.212 in binary is 11000000.10101000.11100001.11010100
0.0.0.31 in binary is 00000000.00000000.00000000.00011111
So, Broadcast ip in binary is 11000000.10101000.11100001.110 11111
So, Broadcast ip in decimal is 192.168.225.223

broadcast ip: 192.168.225.223

venereology answered 3 hours ago

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