Question

URGENT

write a c++ program which asks the user to enter a positive number which is less than or equal to 9. Do not let the user continue until he or she enters a number within range. once a valid number is entered, multiply it by itself. if the resulting number is even, display a message with the number followed by the words even. If it is odd, display the number followed by the words is odd. must use a do-while loop

Answer 1

#include<iostream>
using namespace std;
int main(){
        int n;
        cout<<"Enter a positive number:";
        //reading a positive number in range of 1 to 9.
        do{
                cin>>n;
                //checking entered number is within range or not.
                if(n>0 && n<=9){
                        break;
                }
                else{
                        cout<<"Please enter valid number(1-9):";
                }
        }while(1);
        //multiplying the number by itself.
        n=n*n;
        //checking the number is odd.
        if(n%2==1){
                cout<<n<<" odd"<<endl;
        }
        //checking the number is even.
        else{
                cout<<n<<" even"<<endl;
        }
        return 0;
}
/*Note:- Since 0 is neither positive nor negative this code does
not consider 0 as valid number and hence prompts user to enter 
another number.*/