Question

declare an integer array of n numbers //enter a value for n before the declaration

enter values for the declared array, pass the array to the method that has the name "countNumbers"

let the function countNumber count how many elements of the array in the interval

[70 90] means between 70 and 90 inclusive, returns this count to the main, and prints it using format printing.

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Please Solve As soon as

Solve quickly I get you thumbs up directly

Thank's

Rawan F

Answer 1

The program is done in C with tested code.

#include <stdio.h>

int countNumbers(int *x)
{
    //counter
    int count = 0;
    //length of the array
    int len = sizeof(x)/sizeof(x[0]);
    //loop to pass through the array
    for(int i = 0 ;i < len ; ++i )
    {
        //condition check
         if (x[i]>=70 && x[i]<=90)
         {
            //Updation statement if condition is true
            count+=1;
         }
    }
    //returns the final count
    return count;
}

int main()
{
   //size of the array
   int n=5;
   //array decleration
   int x[n];
   //loop to assign values to the elements of the array
   for(int i =0;i<n;++i)
    {x[i] = 70 + 5*i;}
    
    //formatted print and call of function is merged.
   printf("The count of numbers in the array between 70 and 90 (both inclusive) are %i",countNumbers(x));
   
   return 0;
}

The result:

"The count of numbers in the array between 70 and 90 (both inclusive) are 2"