Question

Radix sortCome up with an unsorted array of numbers (integer array). Sort the numbers in ascending order and descending order and display them using radix sort. First sort in ascending, then reset the array to its original order and finally sort the array again in descending order.

I need this in java language.

Answer 1

SOLUTION -

CODE -

//java code

import java.io.*;
import java.util.*;
import java.util.Arrays;
class Radix{
static int getMax(int arr[], int n)
{
int mx = arr[0];
for (int i = 1; i < n; i++)
if (arr[i] > mx)
mx = arr[i];
return mx;
}
  
static void countSort(int arr[], int n, int exp)
{
int output[] = new int[n]; // output array
int i;
int count[] = new int[10];
Arrays.fill(count,0);
  
for (i = 0; i < n; i++)
count[ (arr[i]/exp)%10 ]++;
  
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
  
for (i = n - 1; i >= 0; i--)
{
output[count[ (arr[i]/exp)%10 ] - 1] = arr[i];
count[ (arr[i]/exp)%10 ]--;
}
  
for (i = 0; i < n; i++)
arr[i] = output[i];
}
  
static void radixsort(int arr[], int n)
{
int m = getMax(arr, n);
  
for (int exp = 1; m/exp > 0; exp *= 10)
countSort(arr, n, exp);
}
  
  
static void print(int arr[], int n)
{
for (int i=0; i<n; i++)
System.out.print(arr[i]+" ");
}
   static void reverse(int a[], int n)
{
int[] b = new int[n];
int j = n;
for (int i = 0; i < n; i++) {
b[j - 1] = a[i];
j = j - 1;
}
  
/*printing the reversed array*/
for (int k = 0; k < n; k++) {
System.out.print(b[k]+" ");
}
}
  
  
  
public static void main (String[] args)
{
int arr[] = {170, 45, 75, 90, 802, 24, 2, 66};
int n = arr.length;
       System.out.println("Original Array");
       for (int i=0; i<n; i++)
System.out.print(arr[i]+" ");
       System.out.println("\nAscending Order ");
radixsort(arr, n);
print(arr, n);
       int arr1[] = {170, 45, 75, 90, 802, 24, 2, 66};
       System.out.println("\nOriginal Array");
       for (int i=0; i<n; i++)
System.out.print(arr1[i]+" ");
       System.out.println("\nDescending Order ");
radixsort(arr, n);
       reverse(arr, n);
   }
   }

output:

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