Question

calculate the fifth ionization energy of nitrogen

Answer 1

he ionization energy is the energy required to remove the most loosely held electron from a gaseous atom or ion. The higher the value of the ionization energy, the harder it is to remove that electron. In the equation above, the subscript “g” indicates that the element is in the form of a gas. The definition for ionization energy specifies “in the gaseous phase” because when the atom or ion is in the liquid or solid phases, other factors are involved. The general equation for the ionization energy is as follows.

A(g)+ENERGY -----> A⁺ + e^- this is first ionization IE1

So if I had to predict the energy for Nitrogen I would draw out a bohr diagram so the atomic number of nitrogen is 7...so 5 electrons in the outer shell and 2 in the first shell. The electronic configuration is [He]2s²2p³ so 1st the 5 electrons in the 2nd shell need to be removed .
Ionisation energy numbers are on the left and the Enthalpy /kJ mol-1 are on the right
1st ------1402.3 kJ mol^-1
2nd -------2856 kJ mol^-1
3rd ---------4578.1 kJ mol^-1
4th ----------7475.0 kJ mol^-1
5th ---------- 9444.9 kJ mol^-1