Question

In: Chemistry

A bottle contains a 0.0525M (

Expert Solution

X- + H2O ----------------------> HX + OH-

0.0525 0 0----------------------------initial

0.0525-x x x --------------------------equilibrium

Kb= [HX][OH-]/[X-]

Kb= x^2/(0.0525-x) -------------------------------(1)

x= [OH-]

we know pH = 10.465

pH+ pOH =14

pOH = 3.535

pOH = -log[OH-]

[OH-]= 10^-pOH= 10^-3.535

[OH-]= 2.91 x 10^-4 M

x= [OH-]= 2.91 x 10^-4

now from (1)

Kb= x^2/(0.0525-x) = (2.91 x 10^-4)^2/(0.0525-2.91 x 10^-4 )

Kb = 1.62 x 10^-6 -------------------------------------------------------------answer

base X- = 0.0525-x =0.0525-2.91 x 10^-4

base [ X-] = 0.0522M -------------------------------------------------answer

queen_honey_blossom answered 2 months ago

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