Ba(NO3)2 + NaIO3 + H2O → Ba(IO3)2·H2O + NaNO3 5.274 g of barium iodate monohydrate was synthesized by a student by addi

Ba(NO₃)₂ + NaIO₃ + H₂O → Ba(IO₃)₂·H₂O + NaNO₃

5.274 g of barium iodate monohydrate was synthesized by a student by adding 30.00 mL of 5.242 x 10^-1 M Ba(NO₃)₂ to 50.00 mL of 8.221 x 10^-1 M NaIO₃.

Calculate the theoretical yield of Ba(IO₃)₂·H₂O in grams.

Expert Solution

queen_honey_blossom answered 2 months ago

determine the molar solubility of Ba(IO3)2 in 0.02000 M Ba(NO3)2 solution.

Calculate the molar solubility of Ca(IO3)2 in a) 0.060 M Ca(NO3)2 b) 0.060 M NaIO3

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