In: Chemistry
determine the molar solubility of Ba(IO3)2 in 0.02000 M Ba(NO3)2 solution.
Ba(IO3)2 ---------> Ba^2+ (aq) + 2IO3^-
s 2s
+0.02
s+0.02 2s
[Ba^2+] = s+0.02 = 0.02M
Ksp = [Ba^2+][IO3^-]^2
4.01*10^-9 = (0.02)(2s)^2
s = 0.000224
molar solubility of Ba(IO3)2 is 0.000224M