Question

In: Statistics and Probability

The survival times in weeks for 20 male rats that were exposed to a high level...

The survival times in weeks for 20 male rats that were exposed to a high level of radiation are152 152 115 109 137 88 94 77 160 165 125 40 128 123 136 101 62 153 83 69. Data are from Lawless (1982) and are stored in the data frame RAT. Load the data with data(RAT)Construct a 95% confidence interval for the average survival time for male rats exposed to high levels of radiation. Round to two decimal places.

Hint: Use T-distribution as sample is small and variance unknown.

CI <- t.test(RAT$survival.time, conf.level = ???)$conf

Solutions

Expert Solution

Solution:

x x2
152 23104
152 23104
115 13225
109 11881
137 18769
88 7744
94 8836
77 5929
160 25600
165 27225
125 15625
40 1600
128 16384
123 15129
136 18496
101 10201
62 3844
153 23409
83 6889
69 4761
x=2269 x2=281755

The sample mean is

Mean = (x / n) )


=152+152+115+109+137+88+94+77+160+165+125+40+128+123+136+101+62+153+83+69/20

=2269 /20

=113.45

Mean =113.45

The sample standard is S

  S =( x2 ) - (( x)2 / n ) n -1

=(281755-(2269)220 /19 )

=(281755-257418.05 /19)

=24336.95/19

=1280.8921

=35.789

The sample standard is = 35.79

Degrees of freedom = df = n - 1 = 20 - 1 = 19

At 95% confidence level the t is ,

  = 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

t /2,df = t0.025,19 =2.093

Margin of error = E = t/2,df * (s /n)

= 2.093 * (35.79 / 20)

= 16.75

Margin of error =16.75

The 95% confidence interval estimate of the population mean is,

- E < < + E

113.45 - 16.75 < < 113.45 + 16.75

96.70 < < 130.20

(96.70, 130.20 )


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