A hydrocarbon with the general formula
CxHy is 92.26% carbon. Experiment shows that
0.311 g hydrocarbon...
A hydrocarbon with the general formula
CxHy is 92.26% carbon. Experiment shows that
0.311 g hydrocarbon fills a 185 mL flask at 88.7 °C with a pressure
of 486 mm Hg.
Calculate the molecular formula for this compound.
A hydrocarbon with general formula CxHy was burned completely in
air, yielding .18g of water and .44 g of carbon dioxide. Which
formula could give such data? Please explain step by step process.
The answer is C2H4 and molar mass for water is 18. g/mol-1 and CO2
is 44.0 g / mol -1
an unkown hydrocarbon contain carbon hydrogen and oxygen
combustion of 1.6 g of the hydrocarbon produces 1.0286 g h2o and
3.7681 g co2. what is the empiral formula of this compound?
An unknown compound contains only carbon and hydrogen (CxHy).
Combustion of this compound produced 3.67 g of carbon dioxide and
1.50 g of water. Determine the molecular formula of this compound
if the molecular mass is between 40 and 45 amu.
As with any combustion reaction, the products of combusting a
hydrocarbon fuel (CxHy) with oxygen (O2) are carbon dioxide (CO2)
and water (H2O).
A mass of 16.89 g for an unknown fuel was combusted in
a reaction vessel containing an unknown amount of oxygen. At the
end of the reaction, there still remained 16.85 g of the fuel as
well as 0.0654 g of water and 0.1198 g of carbon dioxide. The
oxygen was completely consumed during the reaction.
How...
Cumene, a hydrocarbon,
is 89.94% carbon, and its molar mass is 120.2 g/mol.
What are the
a)
empirical and b) molecular
formulas for Cumene? Show your work
A high grade fuel oil which consists of only hydrocarbon, CxHy
is burnt in a combustion chamber at 25 °C. The standard heat of
combustion is -43,515 J/g with CO2 (g) and H2O (l) as products. The
temperature of the fuel and air entering the combustion chamber is
25 °C. The air is assumed dry. The flue gases leave at 300 °C and
their average composition is 11.2 % CO2, 0.4 % CO, 6.2 % O2 and
82.2 % N2...
When 1.661 grams of a hydrocarbon,
CxHy, were burned in a combustion analysis
apparatus, 5.211grams of CO2 and
2.134 grams of H2O were produced.
In a separate experiment, the molar mass of the compound was found
to be 42.08 g/mol. Determine the empirical formula
and the molecular formula of the hydrocarbon.
Enter the elements in the order presented in the question.
Complete combustion of a 0.0150 mol sample of a hydrocarbon,
CxHy, gives 3.024 L of CO2 at STP and 1.891 g of H2O.
(a) What is the molecular formula of the hydrocarbon?
(b) What is the empirical formula of the hydrocarbon?
A 0.500-L bulb containing Ne at 685 torr is connected by a valve
to a 2.50-L bulb containing CO2 at 375 torr. The valve between the
two bulbs is opened and the two gases mix. The initial gas
pressures...
When 5.895 grams of a hydrocarbon,
CxHy, were burned in a combustion analysis
apparatus, 18.50 grams of CO2and
7.574 grams of H2O were produced.
In a separate experiment, the molar mass of the compound was found
to be 42.08 g/mol. Determine the empirical formula
and the molecular formula of the hydrocarbon.
Empirical formula?
Molecular formula?