For simplex method, formulate the model to find out how many
orders for each product should the company accept per day.
- A.
Objective Function: Minimize 75 X1 + 145
X2 + 125 X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
96
0.25 X1 + 0.4X2 + 0.3 X3 <=
24
1 X1 + 1.5 X2 + 1 X3<=
160
0.1 X1 + 0.15 X2 + 0.2 X3 <=
16
0.8X1 - 0.2 X2 - 0.2 X3 >=
0
-0.2 X1 +0.8 X2 - 0.2 X3>=
0
-0.2 X1 - 0.2 X2 + 0.8 X3>=
0
X1, X2 , X3 >=
0
- B.
Objective Function: Maximize 75 X1 + 145
X2 + 125 X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
96
0.25 X1 + 0.4X2 + 0.3 X3 <=
24
1 X1 + 1.5 X2 + 1 X3<=
160
0.1 X1 + 0.15 X2 + 0.2 X3 <=
16
0.8X1 - 0.2 X2 - 0.2 X3 >=
0
-0.2 X1 +0.8 X2 - 0.2 X3>=
0
-0.2 X1 - 0.2 X2 + 0.8 X3>=
0
X1, X2 , X3 >=
0
- C.
Objective Function: Maximize 75 X1 + 145
X2 + 125 X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
96
0.25 X1 + 0.4X2 + 0.3 X3 <=
24
1 X1 + 1.5 X2 + 1 X3<=
160
0.1 X1 + 0.15 X2 + 0.2 X3 <=
16
0.8X1 - 0.2 X2 - 0.2 X3 >=
0
-0.2 X1 +0.8 X2 - 0.2 X3>=
0
-0.2 X1 - 0.2 X2 + 0.8 X3>=
0
- D.
Objective Function: Maximize 75 X1 + 145
X2 + 125 X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
96
0.25 X1 + 0.4X2 + 0.3 X3 <=
24
1 X1 + 1.5 X2 + 1 X3<=
160
0.1 X1 + 0.15 X2 + 0.2 X3 >=
16
X1 >= 0.2(X1 + X2 +
X3)
X2 >= 0.2(X1 + X2 +
X3)
X3 >= 0.2(X1+ X2 +
X3)
- E.
Objective Function: Maximize 75 X1 + 145
X2 + 125 X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
12
0.25 X1 + 0.4X2 + 0.3 X3 <=
3
1 X1 + 1.5 X2 + 1 X3<=
20
0.1 X1 + 0.15 X2 + 0.2 X3 <=
2
X1 >= 0.2
X2 >= 0.2
X3>= 0.2
X1, X2 , X3 >=
0
- F.
Objective Function:
Maximize 75 X1 + 145 X2 + 125
X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
96
0.25 X1 + 0.4X2 + 0.3 X3 <=
24
1 X1 + 1.5 X2 + 1 X3<=
160
0.1 X1 + 0.15 X2 + 0.2 X3 <=
16
0.8X1 - 0.2 X2 - 0.2 X3 <=
0
-0.2 X1 +0.8 X2 - 0.2 X3<=
0
-0.2 X1 - 0.2 X2 + 0.8 X3<=
0
X1, X2 , X3 >=
0
- G.
Objective Function: Maximize 75 X1 + 145
X2 + 125 X3
Subject to:
0.5 X1 + 0.75 X2 + 1.5 X3 <=
12
0.25 X1 + 0.4X2 + 0.3 X3 <=
3
1 X1 + 1.5 X2 + 1 X3<=
20
0.1 X1 + 0.15 X2 + 0.2 X3 <=
2
0.8X1 - 0.2 X2 - 0.2 X3 <=
0
-0.2 X1 +0.8 X2 - 0.2 X3<=
0
-0.2 X1 - 0.2 X2 + 0.8 X3<=
0
X1, X2 , X3 >=
0