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(1.) The electric field inside a parallel plate capacitor is E(t)=E0t3 where E0=100 N/C. If the...

(1.) The electric field inside a parallel plate capacitor is E(t)=E₀t³ where E₀=100 N/C. If the side length of the plates is l=10cm, what is the displacement current at t=4s

4.25x10^-10 A

4.25x10^-6 A

4.25x10^-14 A

4.25x10^-9 A

(1.B) A parallel plate capacitor is made of two circular plates of radius r and has a displacement current I_d=3/t²As². What is the magnitude of the electric field between the plates?

3/πr²ε₀t N/C

-3/πr²ε₀t N/C

-3/πr²ε₀t² N/C

3/πr²ε₀t² N/C

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genius_generous answered 1 year ago

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