In: Accounting
A 335-room hotel property recorded in 2004 a 66.6% occupancy and an ADR of $117.98. What is the property’s franchise fee (1) on a per available room basis and (2) as a percentage of rooms revenue if the agreement required the hotel to pay a reservation fee of $7.65 per available room per month; a royalty fee of 5% of rooms revenue; an advertising fee of 2.3% of rooms revenue; and a frequent traveler program fee of $5.00 per occupied room. The hotel had frequent stay guests totaling 6% of the occupied rooms. The initial fee is a minimum of $45,000 plus $300 per room for each room over 150.
1. Please use the information from Question 1 to calculate the Total franchise fee.
Total franchise fee (round to a whole number) $ ___
2. Please use the information from Question 1 to calculate the Franchise fee on PAR basis.
Franchise fee on PAR basis (round to two decimal places) $___ PAR/yea
3.Please use the information from Question 1 to calculate the Franchise fee as a % of revenue.
Franchise fee as a % of revenue (round to two decimal places) ___%
Total Rooms | = | 335 |
Occupancy | = | 66.60% |
ADR | = | 117.98 |
Revenue per available room (335*66.60%*117.98) | = | Occupancy*ADR |
= | 26,323 | |
Initial Fee {45000+300*(335-150)} | = | 1,00,500 |
(+) Reservation Fee (335*7.65*12) | = | 30,753 |
(+) Royalty Fees (26322.52*335*5%) | = | 4,40,902 |
(+) Advertising Fees (26322*335*2.3%) | = | 2,02,815 |
(+) Frequent Traveler Program (335*66.60%*$5) | = | 1,116 |
(+) Frequent Travel Stay (26323*6%) | = | 1,579 |
Total Franchise Fee | 7,77,665 | |
Franchise Fee per available room (777665/335) | 2,321 | |
Room Revenue | 26,323 | |
Franchise cost | 2,321 | |
% of Room Revenue (2321/26323)*100 | 8.82% |