In: Statistics and Probability
Month |
Chevy Cruze |
Ford Focus |
Hyundai Elantra |
Honda Civic |
Toyota Corolla |
VW Jetta |
January |
21,711 |
21,303 |
21,006 |
19,341 |
20,985 |
19,671 |
February |
18,274 |
19,385 |
19,992 |
20,872 |
19,785 |
19,105 |
March |
17,934 |
16,557 |
15,713 |
17,181 |
16,889 |
16,006 |
April |
19,387 |
17,420 |
15,054 |
14,500 |
14,093 |
14,083 |
May |
17,097 |
16,147 |
15,023 |
15,800 |
15,727 |
16,875 |
June |
16,244 |
16,173 |
14,295 |
15,058 |
15,236 |
16,893 |
a. run the data using ANOVA on Excel. You may choose which ANOVA is most appropriate.
b. Show the Excel ANOVA output and describe what the output means.
Anova: Two-Factor Without Replication | ||||||
SUMMARY | Count | Sum | Average | Variance | ||
January | 6 | 124017 | 20669.5 | 892146.3 | ||
February | 6 | 117413 | 19568.83 | 769914.2 | ||
March | 6 | 100280 | 16713.33 | 653005.1 | ||
April | 6 | 94537 | 15756.17 | 4717579 | ||
May | 6 | 96669 | 16111.5 | 597021.5 | ||
June | 6 | 93899 | 15649.83 | 905859.8 | ||
Chevy Cruze | 6 | 110647 | 18441.17 | 3701180 | ||
Ford Focus | 6 | 106985 | 17830.83 | 4369303 | ||
Hyundai Elantra | 6 | 101083 | 16847.17 | 8305758 | ||
Honda Civic | 6 | 102752 | 17125.33 | 6374508 | ||
Toyota Corolla | 6 | 102715 | 17119.17 | 7349288 | ||
VW Jetta | 6 | 102633 | 17105.5 | 4204497 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
month | 1.4E+08 | 5 | 27947623 | 21.98208 | 2.04E-08 | 2.602987 |
Columns | 10893073 | 5 | 2178615 | 1.71358 | 0.168264 | 2.602987 |
Error | 31784556 | 25 | 1271382 | |||
Total | 1.82E+08 | 35 |
p value for month = 0.0000 , so significant
there is an effect of month
.............
p value for column for 0.168
p value > 0.05
so not significant
.........................
THANKS
revert back for doubt
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