Question

How can I get the days to print in order (Monday, Tuesday, Wednesday etc)

def summarize_by_weekday(expense_list):
"""
Requirement 3 to display the total amount of money spent on each weekday, aggregated per day.
That is, display “Monday: $35”, “Tuesday: $54”, etc., where $35 is the sum of dollar amounts for a
ll Mondays present in the data file, $54 is the sum of dollar amounts for all Tuesdays present in the data file,
and so on.
:param expense_list:
:return: None
"""
  weekday_spent_dict={}
for expense in expense_list:
if weekday_spent_dict.get(expense[0])==None:
weekday_spent_dict[expense[0]]=expense[1]
else:
weekday_spent_dict[expense[0]] += expense[1]
for day in sorted(weekday_spent_dict.keys()):
print('{0}: ${1:5.2f}'.format(day,weekday_spent_dict.get(day)))

output is:

Enter 1 display all of the expense records
2 to display all of the expense records for a particular category
3 to display the total amount of money spent on each weekday, aggregated per day
0 to quit.3
Friday: $94.90
Monday: $40.75
Saturday: $201.38
Sunday: $305.44
Thursday: $276.49
Tuesday: $14.85
Wednesday: $14.85

I want it to print:

Monday

Tuesday

Wednesday

etc..

def get_data(fname):
fileObj = open(fname)
lines = fileObj.readlines()
expense_list = []

for line in lines[1:]: # for lines starting at 2 (excluding 1 because it is the
line_items = line.strip().split(",") # strip removes the newline character
expense_list.append([line_items[0], float(line_items[1]), line_items[2]])

return expense_list

Answer 1

def summarize_by_weekday(expense_list):
        """
        Requirement 3 to display the total amount of money spent on each weekday, aggregated per day.
        That is, display “Monday: $35”, “Tuesday: $54”, etc., where $35 is the sum of dollar amounts for all Mondays present in the data file, $54 is the sum of dollar amounts for all Tuesdays present in the data file,
        and so on.
        :param expense_list:
        :return: None
        """
        weekday_spent_dict={}
        for expense in expense_list:
                if weekday_spent_dict.get(expense[0])==None:
                        weekday_spent_dict[expense[0]]=expense[1]
                else:
                        weekday_spent_dict[expense[0]] += expense[1]

        days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
        for day in days:
                if day in weekday_spent_dict:
                        print('{0}: ${1:5.2f}'.format(day, weekday_spent_dict.get(day)))

**************************************************
You can define the ordering of days in a list, and then check the data for each day because monday tuesday etc do not have a ordering on basis of their english names.

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