In: Physics
If 2.00 m3 of a gas initially at STP is placed under a pressure of 5.00 atm, the temperature of the gas rises to 30.0°C. What is the volume?
answer in m3
at STP temperature is T1 = 273.15 k, pressuer P1 is 1 atm, T2 = 300C = 303.15 k
v1 = 2 m^3, V2 = ? , P2 = 5 atm
form ideal gas equation
PV = nRT ===. > P1V1 / P2V2 = T1/T2
V2 = P1V1T2/T1P2
= (1*2*303.15) /( 273.15*5)
= 0. 4439 m^3
so new volume is 0.4439 m^3