If 2.00 m3 of a gas initially at STP is placed under a pressure of 5.00...

If 2.00 m3 of a gas initially at STP is placed under a pressure of 5.00 atm, the temperature of the gas rises to 30.0°C. What is the volume?

answer in m3

Expert Solution

at STP temperature is T1 = 273.15 k, pressuer P1 is 1 atm, T2 = 30⁰C = 303.15 k

v1 = 2 m^3, V2 = ? , P2 = 5 atm

form ideal gas equation

PV = nRT ===. > P1V1 / P2V2 = T1/T2

V2 = P1V1T2/T1P2

= (1*2*303.15) /( 273.15*5)

= 0. 4439 m^3

so new volume is 0.4439 m^3

genius_generous answered 4 months ago

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