In: Chemistry
The equilibrium constant, K, for the reaction below is 57.0 at 700K
Hydrogen gas plus iodine gas yields hydrogen iodide gas.
Write the balanced equation for the reaction. If 1.00 mol of hydrogen gas is allowed to react with 1.00 moles of iodine gas in a 10.0 Liter container, what are the concentrations of each gas at equilibrium?
Given H2(g) + I2(g)
2HI ; K = 57.0 at 700 K
Molarity of H2 is M =
Molarity of I2 is M' =
H2(g) + I2(g)
2HI
initial mole 1.00 1.00 0
Eqb mole 1.00 -a 1.00 -a 2a Here 2a = number of moles of HI at Equilibrium
Eqb conc
(in mol/L)
Equilibrium constant ,
On solving we get a = 0.79 mol/L
Equilibrium concentration of HI = 2a = 2x0.79 = 1.58 mol/L
Equilibrium concentration of H2 =
Equilibrium concentration of I2 =