Question

In: Chemistry

The equilibrium constant, K, for the reaction below is 57.0 at 700K Hydrogen gas plus iodine...

The equilibrium constant, K, for the reaction below is 57.0 at 700K

Hydrogen gas plus iodine gas yields hydrogen iodide gas.

Write the balanced equation for the reaction. If 1.00 mol of hydrogen gas is allowed to react with 1.00 moles of iodine gas in a 10.0 Liter container, what are the concentrations of each gas at equilibrium?

Solutions

Expert Solution

Given H2(g) + I2(g) 2HI   ; K = 57.0 at 700 K

Molarity of H2 is M =

Molarity of I2 is M' =

                           H2(g) +    I2(g)      2HI  

initial mole           1.00          1.00              0

Eqb mole          1.00 -a            1.00 -a             2a            Here 2a = number of moles of HI at Equilibrium

Eqb conc                             (in mol/L)

Equilibrium constant ,

                           

                

                 

On solving we get a = 0.79 mol/L

Equilibrium concentration of HI = 2a = 2x0.79 = 1.58 mol/L

Equilibrium concentration of H2 =   

Equilibrium concentration of I2 =   


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