Question

1. For the table below, fill in the missing sections for the Mean, Median, Mode, Range, and Standard Deviation on your own. Remember to round to two decimal places.

Hint: Put it in SPSS to simplify the calculation of the standard deviation, using the “Means” test under the Analyze menu!

Then complete the five questions and transfer your answers to the quiz in Canvas

Condition 1 Scores Condition 2 Scores

4, 1, 2, 4, 2, 3, 7, 4, 3, 5, 8, 3 4, 4, 5, 3, 3, 2, 3, 6, 4, 7, 8, 10

Column Mean

Column Median

Column Mode

Standard Deviation

Column Range

1. The correct mean for Condition One is _______ while the correct mean for Condition Two is ______:

A. 4.92 and 3.83

B. 5.17 and 3.42

C. 3.50 and 4.00

D. 3.83 and 4.92

E. 2.04 and 2.39

2. The correct standard deviation for Condition One is ________ while the correct standard deviation for

Condition Two is _______

A. 4.92 and 3.83

B. 5.17 and 3.42

C. 3.50 and 4.00

D. 3.83 and 4.92

E. 2.04 and 2.39

3. Which of the following is true about the mode?

A. Condition One has one mode while Condition Two has two modes

B. Condition Two has one mode while Condition One has two modes

C. The mode(s) for Conditions One and Two are different

D. The mode(s) for Conditions One and Two are the same

4. What is the best interpretation for this t-Test?

A. It was significant,

t

(21.46) = 1.19,

p

< .05

B. It was significant,

t

(22) = 1.19,

p

< .05

C. It was significant,

t

(22) = 0.56,

p

< .001

D. It was not significant,

t

(21.46) = 1.19,

p

> .05

E. It was not significant,

t

(22) = 1.19,

p

> .05

5. Use the Independent Samples Test table as well as your findings for the mean and SDs (from question

#1) to determine which of the following is

t

-Test write-ups correct:

A. We ran an independent samples

t

-Test with score as the dependent variable and condition (1

versus 2) as the independent variable, which was significant,

t

(21.46) = 1.19,

p

< .05. Scores

were higher in condition 1 (

M

= 3.83,

SD

= 2.04) than in condition 2 (

M

= 4.92,

SD

= 2.39).

B. We ran an independent samples

t

-Test with score as the dependent variable and condition (1

versus 2) as the independent variable, which was significant,

t

(22) = 1.19,

p

< .05. Scores were

higher in condition 1 (

M

= 4.92,

SD

= 2.39) than in condition 2 (

M

= 3.83,

SD

= 2.04).

C. We ran an independent samples

t

-Test with score as the dependent variable and condition (1

versus 2) as the independent variable, which was significant,

t

(22) = 1.19,

p

< .05. Scores were

higher in condition 1 (

M

= 3.83,

SD

= 2.04) than in condition 2 (

M

= 4.92,

SD

= 2.39).

D. We ran an independent samples

t

-Test with score as the dependent variable and condition (1

versus 2) as the independent variable, which was not significant,

t

(21.46) = 0.56,

p

> .05. Scores

were higher in condition 1 (

M

= 3.83,

SD

= 2.04) than in condition 2 (

M

= 4.92,

SD

= 2.39).

E. We ran an independent samples

t

-Test with score as the dependent variable and condition (1

versus 2) as the independent variable, which was not significant,

t

(22) = 1.19,

p

> .05. Scores did

not differ significantly between condition 1 (

M

= 3.83,

SD

= 2.04) and condition 2 (

M

= 4.92,

SD

= 2.39).

Answer 1

Using SPSS

1)D

2)E

3)D

4)E The t-value is -1.19445. The p-value is .245022. The result is not significant at p < .05.

5)E (The t-value is -1.19445. The p-value is .245022. The result is not significant at p < .05.)