Question
In: Statistics and Probability
number of absences 6 2 15 9 12 5 8 final grade 82 86 43 74...
| number of absences | 6 | 2 | 15 | 9 | 12 | 5 | 8 |
| final grade | 82 | 86 | 43 | 74 | 58 | 90 | 65 |
The data below were obtained in a study on the number of absences and the final grades (in percentages) of seven randomly selected students in a statistics class. Number of absences 6 2 15 9 12 5 8 Final grade 82 86 43 74 58 90 65 (2 4 6 8 10 12 14 5 0 6 0 7 0 8 0 9 0 absences g ra d e s) (this is just the scattered plot which i could not place here)
3 a) Consider the scatterplot of the data above and describe the association between the number of absences and the final grade. Is linear regression appropriate here?
b) Perform linear regression analysis in SPSS. Write down the linear regression equation that relates the final grades and the number of absences.
c) A 90% confidence interval for x = 10 is (58.996, 69.897). Interpret it.
d) Find a 95% confidence interval for the slope of the regression line.
e) Interpret the slope of the regression line.
f) Interpret the y-intercept of the regression line.
g) What assumptions do you need for performing the linear regression analysis in part b)?
Solutions
orchestra answered 1 year agoRelated Solutions
This is the final grade and number of absences for a set of students. Regress grade...
This is the final grade and number of absences for a set of
students. Regress grade on absences. Use a 95% confidence level.
Give the equation of estimation. Interpret the equation. According
to the regression, now much does a tardy (= 1/2 an absence) change
your grade? Evaluate the model. What evaluation criterion did you
use? Could this be a case of reverse causality? If so, give an
example of how the causation could run in the opposite
direction.
Student...
Table: x: 6, 2, 15, 9, 12, 5, 8 y: 8, 9, 4, 7, 6, 9,...
Table:
x: 6, 2, 15, 9, 12, 5, 8
y: 8, 9, 4, 7, 6, 9, 8
1) Make the scatter diagram.
2) Find the equation of the regression line using the formulas
given in class. They must appear the intermediate steps of
substitutions. Round the answers to three decimal places.
3) Find the correlation coefficient using the formulas given in
class. Steps should appear intermediates of substitutions. Round
the answer to three decimal places.
4) Find the value predicted...
exper score salary 4 78 24 7 100 43 1 86 23.7 5 82 34.3 8...
exper
score
salary
4
78
24
7
100
43
1
86
23.7
5
82
34.3
8
86
35.8
10
84
38
0
75
22.2
1
80
23.1
6
83
30
6
91
33
9
88
38
2
73
26.6
10
75
36.2
1-R2=
2-F test statistic=
3.b2=
4-P-value for F test=
# of OpenLab visits Final grade 2 40 8 85 10 80 9 84 15 90...
# of OpenLab visits
Final grade
2
40
8
85
10
80
9
84
15
90
7
72
5
50
4
59
8
85
10
70
7
66
7
70
5
63
4
60
4
59
11
79
3
82
9
90
10
82
9
76
14
85
6
73
5
41
4
56
8
80
10
70
7
66
9
88
5
65
4
70
4
62
11
90
In what follows use any of the following tests/procedures:
Regression,...
3 6 4 8 1 10 2 9 11 12 15 22 3 6 7 5...
3
6
4
8
1
10
2
9
11
12
15
22
3
6
7
5
8
1
12
14
Each column represents a different treatment given to sick rats.
Each cell is a different rat. Use statistical analysis and use post
hoc testing using contrasts to find the best
treatment.
Treatment 1: vitamins
Treatment 2: prescription pills
Treatment 3: brain surgery
Treatment 4: shock therapy
Treatment 5: dietary changes
Periods 1% 2% 3% 4% 5% 6% 7% 8% 9% 10% 12% 14% 15% 16% 18%...
Periods
1%
2%
3%
4%
5%
6%
7%
8%
9%
10%
12%
14%
15%
16%
18%
20%
1
0.990
0.980
0.971
0.962
0.952
0.943
0.935
0.926
0.917
0.909
0.893
0.877
0.870
0.862
0.847
0.833
2
0.980
0.961
0.943
0.925
0.907
0.890
0.873
0.857
0.842
0.826
0.797
0.769
0.756
0.743
0.718
0.694
3
0.971
0.942
0.915
0.889
0.864
0.840
0.816
0.794
0.772
0.751
0.712
0.675
0.658
0.641
0.609
0.579
4
0.961
0.924
0.888
0.855
0.823
0.792
0.763
0.735
0.708
0.683
0.636...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
Day
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Number of Aides Absent
5
8
11
15
4
2
7
1
4
6
14
19
3
5
8
In which of the following ranges you can find the Upper Control
Limit of the control chart?
0.1427
0.1536
0.1677
Not computable with information available
In which of the following ranges you can find the Lower Control
Limit of the control chart?
Does not exit...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
student
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Test score
67
67
87
89
87
77
73
74
68
72
58
98
98
70
77
Above we have the final averages of the last stats and I want to
know if the class average falls within the boundaries of all my
statistics classes for the past 20 years.
Find the sample size, mean, and standard deviation of the data
above (Table 1)....
Shoe Size 12 6 11 13 8 9 8 8 9 9 11 5 10 8...
Shoe Size
12
6
11
13
8
9
8
8
9
9
11
5
10
8
7
7
11
9
9
9
12
8
8
8
12
9
11
8
11
8
13
5
9
8
11
We need to find the confidence interval for the SHOE SIZE
variable. To do this, we need to find the mean and standard
deviation with the Week 1 spreadsheet. Then we can the Week 5
spreadsheet to find the confidence interval. This does...
Data: 7,-5, -8, 7, 9, 15, 0, 2, 13, 8, 6, -2, 4 (a) Mean= Mode=...
Data: 7,-5, -8, 7, 9, 15, 0, 2, 13, 8, 6, -2, 4 (a) Mean= Mode=
median= (b) Variance= Standard deviation= (c) Range=
IQR(Interquartilerange)= (d) Mid-Range= Mid-Hinge=
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