Question

In: Statistics and Probability

Consider a sample with 10 observations of 2, 3, 10, 13, 12, 5, –1, 10, 2,...

Consider a sample with 10 observations of 2, 3, 10, 13, 12, 5, –1, 10, 2, and 12. Use z-scores to determine if there are any outliers in the data; assume a bell-shaped distribution. (Round your answers to 2 decimal places. Negative values should be indicated by a minus sign.)

The z-score for the smallest observation
The z-score for the largest observation
There are in the data.

Consider the following data for two investments, A and B:

Investment A: x¯x¯ = 7 and s = 4
Investment B: x¯x¯ = 8 and s = 6

Given a risk-free rate of 1.90%, calculate the Sharpe ratio for each investment. (Round your answers to 2 decimal places.)

Sharpe Ratio
Investment A
Investment B

Solutions

Expert Solution

For the given observations mean and standard deviation are calculated

2, 3, 10, 13, 12, 5, –1, 10, 2, 12

Mean:

Standard deviation:

x
2 -4.8 23.04
3 -3.8 14.44
10 3.2 10.24
13 6.2 38.44
12 5.2 27.04
5 -1.8 3.24
-1 -7.8 60.84
10 3.2 10.24
2 -4.8 23.04
12 5.2 27.04

Z-score is calculated as below

The lowest value of x is -1. Hence, the z-score for the smallest observation is given as

The highest value of x is 13. Hence, the z-score for the largest observation is given as

Since, the z-score of the smallest and largest observation are with in the range of 1.95 (limit for 95%) we can say that there are no outliers.

Final Answer:

The z-score for the smallest observation -1.52

The z-score for the largest observation 1.21

There are no outliers in the data.

2.

Hence, for the given = 7 and s = 4, the sharpe's ratio for investment A with risk free rate of 1.90% is given as

For the given = 8 and s = 6, the sharpe's ratio for investment B with risk free rate of 1.90% is given as

Final answers:

Sharpe Ratio
Investment A 1.28
Investment B 1.02

Related Solutions

Consider the data. xi 1 2 3 4 5 yi 3 7 5 10 13 (a)...
Consider the data. xi 1 2 3 4 5 yi 3 7 5 10 13 (a) Compute the mean square error using equation s2 = MSE = SSE n − 2  . (Round your answer to two decimal places.) (b) Compute the standard error of the estimate using equation s = MSE = SSE n − 2  . (Round your answer to three decimal places.) (c) Compute the estimated standard deviation of b1 using equation sb1 = s Σ(xi −...
LAB9B.DAT 1 10 0.802 2 12 2.176 3 7 0.261 4 13 1.618 5 13 2.033...
LAB9B.DAT 1 10 0.802 2 12 2.176 3 7 0.261 4 13 1.618 5 13 2.033 6 15 4.094 7 15 2.201 8 8 0.902 9 8 1.185 10 12 1.734 11 3 0 12 10 1.477 13 19 3.801 14 13 1.732 15 14 2.747 16 10 0.304 17 7 1.627 18 11 1.726 19 0 0 20 12 2.222 21 14 2.908 22 12 2.261 23 11 0.972 24 13 1.779 25 10 1.194 26 15 3.447 27...
Consider the following data: X Y 1 13 3 10 5 9 5 5 6 3...
Consider the following data: X Y 1 13 3 10 5 9 5 5 6 3 Draw a Scatter Plot of the data. Do you believe the correlation coefficient r will be positive, negative or close to zero? Why What is your estimate to the value of Y associated with X=4?
Match No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14...
Match No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Player A 8 42 56 68 91 123 12 46 57 137 5 80 14 10 19 Player B 38 44 46 59 57 61 48 42 51 39 58 41 55 45 68 1. For the given data set representing the runs scored by two players in last 15 matches, conduct the following analysis: i. Which average you will use to summarize...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Number of Aides Absent 5 8 11 15 4 2 7 1 4 6 14 19 3 5 8 In which of the following ranges you can find the Upper Control Limit of the control chart? 0.1427 0.1536 0.1677 Not computable with information available In which of the following ranges you can find the Lower Control Limit of the control chart? Does not exit...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Test score 67 67 87 89 87 77 73 74 68 72 58 98 98 70 77 Above we have the final averages of the last stats and I want to know if the class average falls within the boundaries of all my statistics classes for the past 20 years. Find the sample size, mean, and standard deviation of the data above (Table 1)....
Company ID 1 2 3 4 5 6 7 8 9 10 11 12 13 14...
Company ID 1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 5330 6352 6340 3399 6566 7376 6882 1842 7362 8205 6222 7695 1681 2283 2 7972 5941 2861 3290 1019 7399 6442 8003 5092 4634 7569 2538 2619 7932 3 8545 6667 2121 2339 4770 7296 3215 7919 2176 9129 1321 695 7945 1673 4 4578 466 4142 8350 7439 6085 8381 5872 2703 6974 702 5846 7176 9179 5 7302 2727 3103...
Consider the following time series. t 1 2 3 4 5 yt 6 10 8 13...
Consider the following time series. t 1 2 3 4 5 yt 6 10 8 13 15 (a) Choose the correct time series plot. (i) (ii) (iii) (iv) What type of pattern exists in the data? (b) Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series. If required, round your answers to two decimal places. y-intercept, b0 = 4.1 Slope, b1 = 2.1 MSE = ???? (c) What is the...
Consider a sample with six observations of 13, 13, 7, 23, 20, and 20. Compute the...
Consider a sample with six observations of 13, 13, 7, 23, 20, and 20. Compute the z-score for each observation. (Leave no cells blank - be certain to enter "0" wherever required. Round your answers to 2 decimal places. Negative values should be indicated by a minus sign.)
5.) For the data set 2 4 4 5 7 8 9 10 12 12 13...
5.) For the data set 2 4 4 5 7 8 9 10 12 12 13 13 16 16 16 16 17 19 19 20 23 24 24 24 25 26 26 27 28 28 29 31 32 34 34 36 37 38 42 44 45 46 47 47 48 50 52 53 53 54 55 56 56 57 58 (a) Find the 80th percentile. The 80t percentile is =    (a) Find the 42nd percentile. The 42nd percentile is...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT